Oct 25th 2011, 20:25:20
So I have the absolute laziest Discrete Math professor in the history of professors who hands out homework that is 10x harder then anything in the lecture notes and includes steps not even covered there and then blows off questions/criticism from students with "It's good you are having a hard time with this, it's like the pain of lifting weights to get stronger"
So long story short I am just trying to pass this class and never have to take a math class again. I'm stuck on this, the last problem in the homework. I've got part 1 down but have no clue wtf to do on Part 2:
4) Prove the sets defined below are equal.
A = { (a, b) ∈ ℤ+ × ℤ+ | a is a factor of b }
B is defined recursively by
Initial Step: (1, 1) ∈ B
Recursive Step: [(a, b) ∈ B and k ∈ ℤ +] therefore [(ak, bk) ∈ B and (a, bk) ∈ B]
Overall strategy: To prove A = B, you must show A ⊆ B and B ⊆ A.
Part 1. To show A ⊆ B, prove the statement “If (r, s) ∈ A then (r, s) ∈ B.”
Begin with an arbitrary element of A, say (a, b) ∈ A. Then you must show (a, b) ∈
B. Hint: show how to use the recursive definition of B to build (a, b) (using the
recursive step finitely many times). Hint: Note that if (a, b) ∈ A, a and b are positive
integers such that a is a factor of b, and there is another integer k with ak = b.
Part 2. To show B ⊆ A, use structural induction to prove “If (r, s) ∈ B then (r, s) ∈ A.
So long story short I am just trying to pass this class and never have to take a math class again. I'm stuck on this, the last problem in the homework. I've got part 1 down but have no clue wtf to do on Part 2:
4) Prove the sets defined below are equal.
A = { (a, b) ∈ ℤ+ × ℤ+ | a is a factor of b }
B is defined recursively by
Initial Step: (1, 1) ∈ B
Recursive Step: [(a, b) ∈ B and k ∈ ℤ +] therefore [(ak, bk) ∈ B and (a, bk) ∈ B]
Overall strategy: To prove A = B, you must show A ⊆ B and B ⊆ A.
Part 1. To show A ⊆ B, prove the statement “If (r, s) ∈ A then (r, s) ∈ B.”
Begin with an arbitrary element of A, say (a, b) ∈ A. Then you must show (a, b) ∈
B. Hint: show how to use the recursive definition of B to build (a, b) (using the
recursive step finitely many times). Hint: Note that if (a, b) ∈ A, a and b are positive
integers such that a is a factor of b, and there is another integer k with ak = b.
Part 2. To show B ⊆ A, use structural induction to prove “If (r, s) ∈ B then (r, s) ∈ A.
Smarter than your average bear.